Question #115778
2.50 · 104 moving at a speed of 4.00 m / skg wheel railwere moving in the same direction together at an initial speed of 2.00 m / s, each of which was 2.50 · 104kgcollided with a series of three wheelchairs interlocking with the massThe four-wheeler began to move in the same direction. A) Post-conflict 4What is the speed of the wheelchair? B) How much mechanical energy was lost in the collision?is it
1
Expert's answer
2020-05-15T08:46:01-0400

a)


mv+3mu=(4m)Vmv+3mu=(4m)V

V=0.25(v+3u)=0.25(4+3(2))=2.5msV=0.25(v+3u)=0.25(4+3(2))=2.5\frac{m}{s}

b)


ΔE=0.5mv2+0.5(3mu2)0.5(4mV2)=0.5m(v2+3u24V2)ΔE=0.5mv ^2 +0.5(3mu ^2 )−0.5(4mV ^ 2 )\\=0.5m(v ^ 2 +3u ^ 2 −4V ^ 2 )

ΔE=0.5(25000)(42+3(2)24(2.5)2)=37500 JΔE=0.5(25000)(4 ^ 2 +3(2) ^ 2 −4(2.5) ^ 2 )=37500\ J


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