Given data
Mass of block m= 2.5 kg
Acceleration due to gravity g= 9.80 m/s2
Applied force is F= 16 N
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a)
The work done by the applied force is
"W_F=Fd cos25^o=(16 N)(2.2 m) cos25=31.9 N= 32 J"
b)
The work done by the normal force exerted by the table, is
"W_N= Nd cos90^o=Nd(0) = 0 J"
c)
The work done by the gravitational force is
"W_G= F_Gd cos90^o=F_Gd = 0 J"
d)
The total work done is
"W_Total= W_F+W_N+ W_G= 32 J"
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