The magnitude and direction of the Coriolis force on the ball:
"F_c=2mv\u03a9\\text{ sin}\\phi=\\\\\n=2mv\\frac{2\\pi R_e}{T_e}\\text{ sin}\\phi=\\\\\n=2\\cdot0.05\\cdot70\\cdot\\frac{2\\pi (6375\\cdot10^3)}{24\\cdot3600}\\text{ sin}60^\\circ=4.4\\cdot10^{-5}\\text{ N}"
due east.
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