Solution.
m1=60kg;
m2=100kg;
l=4.50m;
υ=T2πR;
The period of rotation of the needle:
T=12hr=43200s;
Needle rotation speed:
v=43200s2⋅3.14⋅4.50m=0.0006541m/s;
Kinetic energy of needle movement:
Wk=2mv2;
Wk=2160kg⋅(0.0006541m/s)2=0.0000342J;
Answer: Wk=0.00003442J.
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