1.)
Here we have to find the electric field vector at origin then the r=x0 and the direction of electric field will be in the direction of negative x as every small part of the rod is creating electric field in negative x at origin
let the linear charge charge density of the rod be "\\lambda"
"dE=k\\smallint\\frac{\\lambda dx}{x^2}"
"E=k\\smallint^{x_0}_{\\infin}\\frac{\\lambda dx}{x^2}"
"E=\\dfrac{k\\lambda}{x_o}(-i)"
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