Question #105668

Consider three point charges at the corners of a triangle where q1 = 6.00 nC, q2 = -2.00 nC and q3 = 5.00 nC. Find the components of force F12, F32, resultant force on q2 in terms of magnitude and direction.

Expert's answer


As we are not provided with the length of the triangle so I have considered it as r

I have attached the diagram of the question

F1=kq1q2r2=9×109×6×2×1018r2=108r2nF\frac{kq_1q_2}{r^2}=\frac{9\times10^9\times6\times2\times10^{-18}}{r^2}=\frac{108}{r^2}nF


F2=kq1q2r2=9×109×5×2×1018r2=90r2nF\frac{kq_1q_2}{r^2}=\frac{9\times10^9\times5\times2\times10^{-18}}{r^2}=\frac{90}{r^2}nF


We will find the find the resultant of these two vectors using the formula

Fnet=F12+F22+2F1F2cos60o\sqrt{F_1^2+F_2^2+2F_1F_2\cos60^o}


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