As we are not provided with the length of the triangle so I have considered it as r
I have attached the diagram of the question
F1="\\frac{kq_1q_2}{r^2}=\\frac{9\\times10^9\\times6\\times2\\times10^{-18}}{r^2}=\\frac{108}{r^2}nF"
F2="\\frac{kq_1q_2}{r^2}=\\frac{9\\times10^9\\times5\\times2\\times10^{-18}}{r^2}=\\frac{90}{r^2}nF"
We will find the find the resultant of these two vectors using the formula
Fnet="\\sqrt{F_1^2+F_2^2+2F_1F_2\\cos60^o}"
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