Answer to Question #174096 in Electric Circuits for ronald canino

Question

an electrician experienced a mild shock when he accidentally touched a wire carrying 5.0 ma for approximately 1.0 s. how many electrons constitute the given current?

Answer 1

GIVEN:

$I=5.0 mA \\t=1.0sec.$

Solution:

as we know that,

Q= charge flows through a wire in given time.

$\boxed{Q=It}$

$\therefore$ $Q=5*{10}^{-3} C$ ......................(1)

and from defini tion of charge we know that

Q=total no. of electrons *charge on a electron

i.e,

$\boxed{Q=ne}$

therefore, putting

value Q from (1) = $Q=5*{10}^{-3} C$

value of $e=1.6*10^{-19} C$

we get;

$5*10^{-3}=n*(1.6*10^{-19})\\\therefore \boxed{n=3.125*10^{16}}$ no. of electrons (answer)