Find the for e between the two charge particles q1= +5 micro-Coulombs and q2= -1 micro-Coulombs and separated 5cm
Given,
q1=5μCq_1=5\mu Cq1=5μC
q2=−1μCq_2=-1\mu Cq2=−1μC
d=5cmd=5cmd=5cm
F=q1×q24πϵd2F=\frac{q_1\times q_2}{4\pi \epsilon d^2}F=4πϵd2q1×q2
=5×10−12×9×109(0.05)2=\frac{5\times 10^{-12}\times 9\times 10^{9}}{(0.05)^2}=(0.05)25×10−12×9×109
=18N=18N=18N
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