The electrical flux density between two plates separated by polystyrene of relative permittivity 2.5 is 5µ C/m2 . Find the voltage gradient between the plates.
The voltage gradient is:
"E=\\frac{D}{\\varepsilon_0 \\varepsilon},"
where D - the electrical flux density;
"\\varepsilon_0" - the vacuum permittivity;
"\\varepsilon" - relative permittivity of polystyrene.
"E=\\frac{5\\cdot 10^{-6}}{8.85\\cdot 10^{-12} \\cdot 2.5}\\approx 226\\space kV\/m."
Answer: 226 kV/m
Comments
This is awesome
Leave a comment