As per the question,
Initially the capacitor was filled with the di-electric material. Now when we will pull the di-electric material, then there will be a force on the dielectric which pulls it into the capacitor and electric potential energy is converted into kinetic energy of the dielectric.
When the di-electric will reach to the equilibrium position, then it will have the kinetic energy and will overshoot the static equilibrium position and eventually end up at rest jest outside the capacitor on the other side from where it started.
The magnitude of the force "F=\\dfrac{\\epsilon_o bV^2(K-1)}{2d}"
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