1electron=1.6×10−19C1electron=1.6\times10^{-19}C1electron=1.6×10−19C
So, 4×1024electrons=6.4×105C4\times10^{24}electrons=6.4\times10^5C4×1024electrons=6.4×105C
Hence, 6.4×105C6.4\times10^5C6.4×105C pass into the solution of silver chloride.
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