Answer to Question #113293 in Electric Circuits for DD

Question

20 kHz audio signal is amplitude modulated over a 100 kHz carrier frequency. The peak amplitude of carrier wave is 10 V. If the modulation index is 0.8, find out the frequencies present in the modulated output. Also calculate the ratio of maximum and the minimum amplitude of the envelope of modulated signal.

Answer 1

the frequencies present in the modulated output. The ratio of maximum and the minimum amplitude of the envelope of modulated signal.

$f_1=f_c-f_s=100-20=80kGz;\\f_2=f_c+f_s=100+20=120kGz;\\index=\frac{A_s}{A_c};A_s=0.8\times10=8V;\\A_{max}=10+8=18V;A_{min}=10-8=2V;\\\frac{A_{max}}{A_{min}}=\frac{18}{2}=9$