Question #160309

A slack rope walker balances on a rope tied between two trees. For a short, he is not moving. His mass is 72 KG. The rope makes an angle of 22 degrees with the horizontal on either side . What is the magnitude of the Tension in the rope ?


1
Expert's answer
2021-02-01T08:07:25-0500

external forces acting on the system:\text{external forces acting on the system:}

Fnet=mg the force of gravityF_{net}=mg\text{ the force of gravity}

T1,T2 directed in different directions along the ropeT_1,T_2 \text{ directed in different directions along the rope}

to the suspension points\text{to the suspension points}

due to the symmetry of the system, the values of \text{due to the symmetry of the system, the values of }

T1 and T2are equal T1=T2T_1\text{ and }T_2 \text{are equal }T_1=T_2

the system is in equilibrium therefore the projections of the forces on the axis are 0\text{the system is in equilibrium therefore the projections of the forces on the axis are 0}

Fnety=T1y+T2yF_{net y}=T_{1y}+T_{2y}

Fnety=FnetF_{net y}=F_{net}

T1y=TsinαT_{1y}=T*\sin\alpha

T2y=TsinαT_{2y}=T*\sin\alpha

T=Fnet2sinα=mg2sinα=729.82sin220941.8T=\frac{Fnet}{2*\sin{\alpha}}=\frac{mg}{2*\sin{\alpha}}=\frac{72*9.8}{2*\sin22^0}\approx 941.8

Answer:941.8 N




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