external forces acting on the system:
Fnet=mg the force of gravity
T1,T2 directed in different directions along the rope
to the suspension points
due to the symmetry of the system, the values of
T1 and T2are equal T1=T2
the system is in equilibrium therefore the projections of the forces on the axis are 0
Fnety=T1y+T2y
Fnety=Fnet
T1y=T∗sinα
T2y=T∗sinα
T=2∗sinαFnet=2∗sinαmg=2∗sin22072∗9.8≈941.8
Answer:941.8 N
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