Answer to Question #159934 in Classical Mechanics for Ange

Question #159934
Two objects attract each other with a gravitational force of magnitude 1.00 x 10^(-8)N when separated by 20.0 cm. If the total mass of the 2 objects is 5.00 kg, what is the mass of each?
1
Expert's answer
2021-02-22T10:29:16-0500

Let the first mass be m1=mm_1=m. Then, the second one will be m2=5.0 kgm.m_2=5.0\ kg -m.

Let’s write the Law of Universal Gravitation:


F=Gm1m2r2.F=\dfrac{Gm_1m_2}{r^2}.

Let's substitute the numbers:


1.0108=6.671011(5.0mm2)(0.2)2,1.0\cdot10^{-8} = \dfrac{6.67\cdot10^{-11}\cdot(5.0m-m^2)}{(0.2)^2},1.0108(0.2)26.671011=5.0mm2,\dfrac{1.0\cdot10^{-8}\cdot(0.2)^2}{6.67\cdot10^{-11}}=5.0m-m^2,m25m+6=0.m^2-5m+6=0.

This uadratic eqqquation has two roots:


m1=b+b24ac2a=5+5241621=3 kg,m_1=\dfrac{-b+\sqrt{b^2-4ac}}{2a}=\dfrac{5+\sqrt{5^2-4\cdot1\cdot6}}{2\cdot1}=3\ kg,m2=bb24ac2a=55241621=2 kg.m_2=\dfrac{-b-\sqrt{b^2-4ac}}{2a}=\dfrac{5-\sqrt{5^2-4\cdot1\cdot6}}{2\cdot1}=2\ kg.

Answer:

m1=3 kg,m2=2 kg.m_1=3\ kg, m_2=2\ kg.


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