As per the given question,
total number of particle = 10
there is two partition of the volume.
So the probability of the particle be in half = 1/2
now as per the probability distribution function,
probability of the particle 5 particle left side "=\\dfrac{1}{2^5}"
similarly, probability of the 10 particle to be left side ="\\dfrac{1}{2^{10}}"
Hence the required ratio = "2^5"
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