Question #108551

a particle of mass 4kg moving with a velocity of 2 m/s collides elastically with particle of mass 6kg moving with velocity of -4m/s.what is the centre of mass?

Expert's answer

As per the given question,

Mass of the particle (m1)=4kg(m_1)=4kg

Velocity of the object (v1)=2m/sec(v_1)=2 m/sec

Mass of the second (m2)=6kg(m_2)=6kg

Velocity of the second object (v2)=−4m/sec(v_2)=-4m/sec

So, Vcom=m1v2+m2v2m1+m2V_{com}=\dfrac{m_1v_2+m_2v_2}{m_1+m_2}


⇒Vcom=4×2−6×44+6\Rightarrow V_{com}=\dfrac{4\times 2-6\times 4}{4+6}


⇒Vcom=8−2410=−1610=−1.6m/sec\Rightarrow V_{com}=\dfrac{8-24}{10}=\dfrac{-16}{10}=-1.6m/sec

Hence the velocity of center of mass will be Vcom=−1.6m/secV_{com}=-1.6m/sec


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