As per the given question,
Mass of the particle (m1)=4kg
Velocity of the object (v1)=2m/sec
Mass of the second (m2)=6kg
Velocity of the second object (v2)=−4m/sec
So, Vcom=m1+m2m1v2+m2v2
⇒Vcom=4+64×2−6×4
⇒Vcom=108−24=10−16=−1.6m/sec
Hence the velocity of center of mass will be Vcom=−1.6m/sec
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