Question

A tugboat pulls a ship with a constant net horizontal force of 5.00 × 103 N
and causes the ship to move through a harbor. How much work is done on
the ship if it moves a distance of 3.00 km?

Answer 1

As per the given question,

Net horizontal force$= 5.00 × 10^3 N$

Distance moved by the ship (d)$=3km=3000m$

Hence, net work done $(W)= F.d$

$\Rightarrow W= 5.0\times 10^3\times 3\times 10^3J$

$\Rightarrow W=15\times 10^6J$