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Vector Calculus
One of the following laws for dot and cross multiplication of three vectors A , B and C is invalid:
(A.B)C=A(B.C)
A×(B×C)=(A.C)B−(A.B)C
(A×B)×C=(A.C)B−(B.C)A
A×(B×C)≠(A×B)×C
(A.B)C=A(B.C)
A×(B×C)=(A.C)B−(A.B)C
(A×B)×C=(A.C)B−(B.C)A
A×(B×C)≠(A×B)×C
Vector Calculus
Let
a⃗ =5i+2j−3k
, then |a|= ……...
38
√38
4
√4
a⃗ =5i+2j−3k
, then |a|= ……...
38
√38
4
√4
Vector Calculus
Find the projection of the vector
A=i−2j+k
on the vector
B=4i−4j+7K
1/5
4/7
19/9
11/5
A=i−2j+k
on the vector
B=4i−4j+7K
1/5
4/7
19/9
11/5
Vector Calculus
If A=3i-j-4k, B=-2i+4j-3k, C=i+2j-k,find
|A+B+C|
(√101)
(√93)
(√27)
(√95)
|A+B+C|
(√101)
(√93)
(√27)
(√95)
Vector Calculus
Given that
A=3i−2j-k
,
B=2i−4j−3k
and
C=−i+2j+2k
. Find 2A-3B-5C
(√30)
(√15)
(√11)
(√5)
A=3i−2j-k
,
B=2i−4j−3k
and
C=−i+2j+2k
. Find 2A-3B-5C
(√30)
(√15)
(√11)
(√5)
Vector Calculus
Given that
A=3i−2j-k
,
B=2i−4j−3k
and
C=−i+2j+2k
. Find A+B+C
5(√3)
4(√5)
4(√2)
3(√5)
A=3i−2j-k
,
B=2i−4j−3k
and
C=−i+2j+2k
. Find A+B+C
5(√3)
4(√5)
4(√2)
3(√5)
Vector Calculus
Given that
A=−i+2j+2k
. Find the magnitude of A
3
5
(√3)
(√5)
A=−i+2j+2k
. Find the magnitude of A
3
5
(√3)
(√5)
Vector Calculus
The resultant vector C of vectors A and B is perpendicular to vector A. Also magnitudes of vectors A and C are equal. Find the angle between the vectors A and B.
Vector Calculus
how we can draw the quadratic surfaces? and how we know about the direction of hyperbola?
Vector Calculus
Let u = <5, 6>, v = <-2, -6>. Find -2u + 5v.
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#340153 on Dec 2023
#340153 on Dec 2023