Answer on Question #56011 – Math – Vector Calculus
Question
If A=3i−j−4k,B=−2i+4j−3k,C=i+2j−k, find ∣A+B+C∣.
Solution
A+B+C=3i−j−4k−2i+4j−3k+i+2j−k=(3−2+1)i+(−1+4+2)j+(−4−3−1)k=2i+5j−8k.
Then ∣A+B+C∣=22+52+(−8)2=4+25+64=93.
Answer: 93.
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