Question #56008

Given that
A=3i−2j-k
,
B=2i−4j−3k
and
C=−i+2j+2k
. Find A+B+C

5(√3)

4(√5)

4(√2)

3(√5)

Expert's answer

Answer on Question #56008– Math – Vector Calculus

Given that A=3i2j+kA = 3i - 2j + k, B=2i4j3kB = 2i - 4j - 3k and C=i+2j+2kC = -i + 2j + 2k.

Find A+B+C|A + B + C|

Solution

A+B+C=3i2j+k+2i4j3ki+2j+2k=(3+21)i+(24+2)j+(13+2)k=4i4j.A + B + C = 3i - 2j + k + 2i - 4j - 3k - i + 2j + 2k = (3 + 2 - 1)i + (-2 - 4 + 2)j + (1 - 3 + 2)k = 4i - 4j.


If a=(ax,ay,az)a = (a_x, a_y, a_z) then a=ax2+ay2+az2|a| = \sqrt{a_x^2 + a_y^2 + a_z^2}.

Thus,


A+B+C=42+(4)2+02=32=42.|A + B + C| = \sqrt{4^2 + (-4)^2 + 0^2} = \sqrt{32} = 4\sqrt{2}.


Answer: A+B+C=42|A + B + C| = 4\sqrt{2}.

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