Answer on Question #56008– Math – Vector Calculus
Given that A=3i−2j+kA = 3i - 2j + kA=3i−2j+k, B=2i−4j−3kB = 2i - 4j - 3kB=2i−4j−3k and C=−i+2j+2kC = -i + 2j + 2kC=−i+2j+2k.
Find ∣A+B+C∣|A + B + C|∣A+B+C∣
Solution
If a=(ax,ay,az)a = (a_x, a_y, a_z)a=(ax,ay,az) then ∣a∣=ax2+ay2+az2|a| = \sqrt{a_x^2 + a_y^2 + a_z^2}∣a∣=ax2+ay2+az2.
Thus,
Answer: ∣A+B+C∣=42|A + B + C| = 4\sqrt{2}∣A+B+C∣=42.
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