Question #53923

Given that P = (-5, 11) and Q = (-6, 4), find the component form and magnitude of vector QP.
1

Expert's answer

2015-08-09T00:00:46-0400

Answer on Question#53923 – Math – Vector Calculus

1. Given that P=(5,11)P = (-5, 11) and Q=(6,4)Q = (-6, 4), find the component form and magnitude of vector QPQP.

Solution.

At first, we will find the components of vector QPQP:


QP=(5(6),114)=(1,7).QP = (-5 - (-6), 11 - 4) = (1, 7).


And now we can find the magnitude of our vector:


QP=QP=12+72=50=52.|QP| = QP = \sqrt{1^2 + 7^2} = \sqrt{50} = 5\sqrt{2}.


Answer:

hence, QP=(1,7)QP = (1,7) and QP=52|QP| = 5\sqrt{2}.

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Comments

Assignment Expert
08.11.17, 11:46

The vector QP is represented as because it starts at Q and ends at P. This vector was discussed in the question. The vector PQ is represented as because it starts at P and ends at Q.

HKK
08.11.17, 05:19

The answer given is wrong. He mixed up Q and P, which left us with instead of . Some expert!

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