Prove that any two open intervals of the real.line are homeomorphic
Solution:
Proof:
Let's show that a bounded open interval (a, b) is homeomorphic to (0,1).
Consider the map f:(0,1) (a, b) defined by f(t)=a+(b-a) t. It is continuous and bijective. It's inverse is continuous as well.
Now let's show that (0,1) is homeomorphic to (a, ). Consider g:(0,1) defined by
This is clearly bijective and continuous. Its inverse is continuous as well.
It's obvious that (-, a) is homeomorphic to (-a, ).
Now we have that (-1,1) is homeomorphic to R using
The property of being homeomorphic is transitive.
Hence, any two open intervals of the real line are homeomorphic.
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