Answer to Question #217052 in Differential Geometry | Topology for Prathibha Rose

Question #217052
Prove that the inverse of a.homeomorphism is also a.homeomorphism
1
Expert's answer
2021-07-27T15:41:12-0400

By definition, a homeomorphism is a bijection such that both f and f1 are continuous. As f is a bijection then by Bijection iff Inverse is Bijection, so is f1. So by definition f1 is a bijection such that both f1 and (f1)1 are continuous. The result follows from Inverse of Inverse of Bijectionwhich states thatLet f:S→T be a bijection. Then: (f1)1=f where f1 is the inverse of f.\text{By definition, a homeomorphism is a bijection such that both f and $f^{−1}$ are}\\\text{ continuous. As f is a bijection then by Bijection iff Inverse is Bijection, so is}\\\text{ $f^{−1}$. So by definition $f^{−1}$ is a bijection such that both $f^{−1}$ and $(f^{−1})^{−1}$ are}\\\text{ continuous. The result follows from Inverse of Inverse of Bijection}\\\text{which states that}\\\text{Let f:S→T be a bijection. Then: $(f^{−1})^{−1}=f$ where $f^{−1}$ is the inverse of f.}


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