Let "x\\in X". Consider the open ball "B" of radius "r" where "r<1". Clearly, "B" is equal to the singleton set "\\{x\\}".
So "x\\in B" and "B" is an improper subset of "\\{x\\}". Hence the set "\\{x\\}" is open. This implies that every singleton set is open, which implies that every subset of "X" is open. So if "Y \\sub X" then "Y^c" is open. Hence "Y" is closed. Thus every subset of a discrete space is closed
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