Question #217032
Prove that any set with the cofinite topology is compact
1
Expert's answer
2021-07-19T14:13:18-0400

Let us prove that any set AA with the cofinite topology is compact. Let U\mathcal U be an open cover of the set A.A. Let U0U_0 is an element of U.\mathcal U. It follows from definition of cofinite topology that AU0A\setminus U_0 is a finite set. Let AU0={x1,,xn}.A\setminus U_0=\{x_1,\ldots, x_n\}. Since U\mathcal U is a cover, for each k{1,,n}k\in\{1,\ldots,n\} there are exists UkUU_k\in\mathcal U such that xkUk.x_k\in U_k. Consequently, U0U1UnAU_0\cup U_1\cup\ldots\cup U_n\supset A and hence, {U0,U1,,Un}U\{U_0,U_1,\ldots, U_n\}\subset\mathcal U is a finite subcover of A.A. We conclude that AA is compact.


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