Question #217030
Prove that any collection of subsets of a set X is a sub base for some topology on X
1
Expert's answer
2021-07-19T14:35:06-0400

Proof: Let B\mathscr{B} be the family of finite intersections of members of S\mathcal{S} . Suppose first that S is a sub-base for I\mathscr{I} . We want to show that I\mathscr{I} is the smallest topology on X containing S\mathcal{S} . Now since SB\mathcal{S} \subset \mathscr{B} and BI\mathscr{B} \subset \mathscr{I} we at least have that I\mathscr{I} contains S. Suppose U\mathcal{U} is some other topology on X such that SU\mathcal{S} \subset \mathcal{U} . We have to show that IU\mathscr{I} \subset \mathcal{U} . Now since U\mathcal{U} is closed under finite intersections and SUS \subset \mathcal{U} , U\mathcal{U} contains all finite intersections of members of S\mathcal{S} ,

i.e. BU\mathscr{B} \subset \mathcal{U} . But again since U\mathcal{U} is closed under arbitrary unions and each member of I\mathscr{I} can be written as union of some members of B\mathscr{B} (by definition of a base), it follows that IU\mathscr{I} \subset \mathcal{U} .


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