Question #217053

Let X be a infinite set with cofinite topology .prove that any bijection from X to X is a homeomorphism

Expert's answer

Let XX be a infinite set with cofinite topology. Let us prove that any bijection f:X→Xf:X \to X is a homeomorphism. Let U⊂XU\subset X be an open set. By definition of cofinite topology, we have that X∖UX\setminus U is finite. Since f:X→Xf: X\to X is a bijection, we conclude that f−1(X∖U)=f−1(X)∖f−1(U)=X∖f−1(U)f^{-1}(X\setminus U)=f^{-1}(X)\setminus f^{-1}(U)=X\setminus f^{-1}(U) and f−1(U)=X∖f−1(X∖U).f^{-1}( U)=X\setminus f^{-1}(X\setminus U). Since X∖UX\setminus U is finite, f−1(X∖U)f^{-1}(X\setminus U) is also finite, and hence f−1(U)f^{-1}( U) is cofinite. We conclude that f−1(U)f^{-1}( U) belongs to the cofinite topology, that is f−1(U)f^{-1}( U) is an open set. Therefore, ff is a continuous map. By analogy, for any open set VV its image f(V)f(V) is cofinite, and hence it is an open set in cofinite topology. We conclude that the map f:X→Xf:X\to X is open, and hence ff is a homeomorphism.



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