Question #217057

Prove that composition of continuous functions from topological spaces to topological spaces is continuous


1
Expert's answer
2021-07-26T15:23:59-0400

Let f:XYf:X\to Y and g:YZg:Y\to Z be a continuous functions of topological spaces. Consider their composition gf:XZ.g\circ f: X\to Z. Let UZU\subset Z be an arbitrary open set. Since gg is continuous, the preimage V=g1(U)V=g^{-1}(U) is open set in Y.Y. Then using the continuity of ff, we conclude that f1(V)f^{-1}(V) is an open set in X.X. Taking into accont that (gf)1(U)=f1(g1(U))=f1(V),(g\circ f)^{-1}(U)=f^{-1}(g^{-1}(U))=f^{-1}(V), we conclude that the preimage of any open set UZU\subset Z is open set in X,X, and hence the composition gf:XZg\circ f: X\to Z is continuous.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS