Question #323845

The number of people arriving for treatment at an emergency room can be modelled by a Poisson process with a mean of five people per hour.

(a) What is the probability that exactly four arrivals occur at a particular hour?

(b) What is the probability that at least four people arrive during a particular hour?

(c) How many people do you expect to arrive during a 45-min period?


1
Expert's answer
2022-04-19T04:42:35-0400

(a) P(X=4)=e5544!=0.1755.P(X=4)=e^{-5}\frac{5^4}{4!}=0.1755.


(b) P(X4)=1P(X<4)=1e5(500!+511!+522!+533!)=0.7350.P(X\ge 4)=1-P(X<4)=1-e^{-5}(\frac{5^0}{0!}+\frac{5^1}{1!}+\frac{5^2}{2!}+\frac{5^3}{3!})=0.7350.


(c) μ=E(X)=54560=3.75.\mu=E(X)=5\frac{45}{60}=3.75.


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