I roll a fair die repeatedly until a number larger than 4 is observed. If N is the total number of times that I roll the die, find P(N = k), for k = 1,2,3,....
The total number of outcomes in each trial is 6, the number of favorable outcomes is 2 (5 and 6 are larger than 4).
Probability of observing a number larger than 4 on a single die roll is "\\cfrac{2} {6} =\\cfrac{1}{3}," probability of ob observing a number less than or equal to 4 is "\\cfrac{2} {3}."
"N=k" means that "k-1" times we had observed a number less than or equal to 4 before we got 5 or 6.
All the rolls are independent events,
"P(N=k) =\\begin{pmatrix}\n \\cfrac{2} {3} \n\\end{pmatrix}^{k-1} \\cdot\\cfrac{1}{3}."
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