A study conducted at a certain college shows that 62% of the school's graduates find a job in their chosen field within a year after graduation. Find the probability that among 5
randomly selected graduates, at least one finds a job in his or her chosen field within a
year of graduating. Round your answer to the nearest thousandth.
n = 5
p = 0.62
(1 - p) = 0.38
As per binomial distribution formula
"P(X = x) = C^n_x \\times p^x \\times (1 - p)^{n - x}"
We need to calculate P(X ≥ 1)
"P(X \u2265 1) = P(X=1) + P(X=2) + P(X=3) + P(X=4) +P(X=5) \\\\\n\nP(X \u2265 1) = (C^5_1 \\times 0.62^1 \\times 0.38^4) + (C^5_2 \\times 0.62^2 \\times 0.38^3) + (C^5_3 \\times 0.62^3 \\times 0.38^2) + (C^5_4 \\times 0.62^4 \\times 0.38^1) + (C^5_5 \\times 0.62^5 \\times 0.38^0) \\\\\n\nP(X \u2265 1) = 0.065 + 0.211 + 0.344 + 0.281 + 0.092 \\\\\n\nP(X \u2265 1) = 0.993"
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