Compute and interpret the correlation coefficient for the aptitude scores and grade point averages in Exercise 8 on page 373.
Since, the data is incomplete, we assume as follows:
Compute and interpret the correlation coefficient for the aptitude scores and grade point averages given as:
Aptitude scores (X) (out of 100) : 78, 85, 92, 98, 52
Grade point average (Y) (out of 10): 8, 9, 9, 9, 5
Solution:
X Values
∑ = 405
Mean = 81
∑(X - Mx)2 = SSx = 1276
Y Values
∑ = 40
Mean = 8
∑(Y - My)2 = SSy = 12
X and Y Combined
N = 5
∑(X - Mx)(Y - My) = 119
R Calculation
r = ∑((X - My)(Y - Mx)) / "\\sqrt{(SS_x)(SS_y)}"
r = 119 / "\\sqrt{(1276)(12)}" = 0.9617
This is a strong positive correlation, which means that high X variable scores go with high Y variable scores (and vice versa).
Comments
Leave a comment