Find the Probabilities on a standard normal curve
1. P(z>—1.32)
2. P(z< 0.45)
3. P(—2.76 < z < 2.76)
4. P(—3.0 < z < —1.68)
5. P(1.53 < z <2.91)
1.) P(Z>—1.32)=P(0<Z<1.32)=0.90P(Z>—1.32) = P(0<Z<1.32) = 0.90P(Z>—1.32)=P(0<Z<1.32)=0.90
2.) P(Z<0.45)=0.67P(Z< 0.45) = 0.67P(Z<0.45)=0.67
3.) P(—2.76<Z<2.76)=2P(0<Z<2.76)=0.99P(—2.76 < Z < 2.76) = 2P(0<Z<2.76) = 0.99P(—2.76<Z<2.76)=2P(0<Z<2.76)=0.99
4.) P(—3.0<Z<—1.68)=P(0<Z<3)+P(0<Z<1.68)=0.045P(—3.0 < Z < —1.68) =P(0<Z<3)+P(0<Z<1.68) = 0.045P(—3.0<Z<—1.68)=P(0<Z<3)+P(0<Z<1.68)=0.045
5.) P(1.53<Z<2.91)=0.061P(1.53 < Z <2.91) = 0.061P(1.53<Z<2.91)=0.061
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