Test marks (%) obtained in a test are normally distributed with a mean of 55% and variance of 400(% squared). What is the probability that a randomly selected student scored above 60%?
"\\mu =55 \\\\\n\n\\sigma = \\sqrt{400} = 20 \\\\\n\nP(X>60) = 1 -P(X<60) \\\\\n\n=1 -P(Z< \\frac{60-55}{20}) \\\\\n\n= 1 -P(Z<0.25) \\\\\n\n= 1 -0.5987 \\\\\n\n= 0.4013"
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