Question #199472

The diameter of an electric cable, Say X, is assumed to be continuous random variable with p.d.f f(x)=6x(1-x), 0<x<1.

A. Show that f(x) is a p.d.f.

B. Determine a number b such that P(X<b)= P(X >b).

C. Find the mean of x.


Expert's answer

A.

Function f(x) is a probability density function in range a to b if

∫abf(x)dx=1\int^b_af(x)dx=1

Then:

∫01(6x(1−x))dx=(3x2−2x3)∣01=3−2=1\int^1_0(6x(1-x))dx=(3x^2-2x^3)|^1_0=3-2=1


C.

E(X)=∫abxf(x)dx=∫01x(6x(1−x))dx=(2x3−1.5x4)∣01=2−1.5=0.5E(X)=\int^b_axf(x)dx=\int^1_0x(6x(1-x))dx=(2x^3-1.5x^4)|^1_0=2-1.5=0.5


B.

P(x<b)=∫0bf(x)dxP(x<b)=\int^b_0f(x)dx

P(x>b)=1−∫0bf(x)dxP(x>b)=1-\int^b_0f(x)dx


Then:

∫0bf(x)dx=1−∫0bf(x)dx\int^b_0f(x)dx=1-\int^b_0f(x)dx

2∫0bf(x)dx=2∫0b(6x(1−x))dx=2(3x2−2x3)∣0b=6b2−4b3=12\int^b_0f(x)dx=2\int^b_0(6x(1-x))dx=2(3x^2-2x^3)|^b_0=6b^2-4b^3=1

b=0.5b=0.5



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