Question #199421

If on the average, (r + 1) cars enter a certain parking lot per minute, what is the probability that during any given minute (i): 4 or more cars will enter the lot? (ii): exactly 4 cars will enter? 


1
Expert's answer
2021-05-31T09:39:10-0400

Poission distribution function

P(X=μ)=λμeλμ!μ=numberofoccurrencesλ=meanP(X=μ) =\frac{ λ^μ e^-λ}{μ!}\\ μ = number of occurrences \\ λ =mean


Given


λ =mean = r+1


(i): 4 or more cars will enter the lot?

λ =mean = r+1

put values in formula



here we will find for 4 or more cars then formula asP(X4)=1P(X<4)=1[P(X=0)+P(X=1)+P(X=2)+P(X=3)]=10μ3(r+1)μe(r+1)μ!here\space we\space will\space find\space for\space 4 \space or\space more\space cars\space then\space formula\space as\\ P(X≥4)=1-P(X<4)\\=1-[P(X=0)+P(X=1)+P(X=2)+P(X=3)]\\ =1-\sum_{0≤μ≤3}\frac{ (r+1)^μ e^{-(r+1)}}{μ!}\\

(ii): exactly 4 cars will enter? 

μ = number of occurrences =4

λ =mean = r+1

put values in formula



P(X=4)=(r+1)4e(r+1)4!P(X=4) =\frac{ (r+1)^4 e^{-(r+1)}}{4!}\\

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