a) We first check for randomness and independence. Once the conditions are satisfied we assume normality.
b) 88% CI= "\\hat p\u00b1z^*\\sqrt{\\frac{\\hat p(1-\\hat p)}{n}}"
"\\hat p=\\frac {95}{178}" =0.5337
"=0.5337\u00b11.55\\sqrt{\\frac{0.5337*(1-0.5337)}{178}}"
=(0. 4758,0.5916)
We are 88% Confident that the population proportion range between 0.4758 and 0.5916.
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