Mean ="\\sum X. P(X)"
=(-10*0.5)+(1*0.25)+(3*0.15)+...+(20*0.01)
=-3.2
Variance ="\\sum X^2 P(X) - \\mu ^2"
"=((-10^2*0.5)+(1^2*0.25)+...+(20^2*0.01))-(-3.2^2)"
=14.36
Standard deviation ="\\sqrt {variance}"
="\\sqrt {14.36}"
=3.879
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