Answer to Question #152035 in Statistics and Probability for JG

Question #152035
The following table represents a sample of 500 people and their opinion on Tax Reform. Do we have enough evidence to conclude that Party Affiliation and Opinion on Tax Reform are dependent on 5% level of significance.

Affiliation/Opinion on Tax | Reforms | Favor | Indifferent | Opposed
---------------------------------------------------------------------------------------------------------------
Democrat
---------------------------------------------------------------------------------------------------------------
Republican
1
Expert's answer
2020-12-25T12:44:03-0500


To test independence of two attributes we use chi-square test.

The given information is:



number of rows m=2

number of column n=3

Hypothesis:

H0 - The Party Affiliation and Opinion on Tax Reform are independent.

H1 - The Party Affiliation and Opinion on Tax Reform are dependent.

Test statistic:

"\u03c7^2 = \\sum_{n}^{j=1} \\sum_{m}^{i=1} \\frac{(O_{ij}-E_{ij})^2}{E_{ij}} \\\\ \n\n\u03c7^2 = \\sum_{n}^{j=1} \\sum_{m}^{i=1} \\frac{O_{ij}^2}{E_{ij}} - N"

Is follow χ2 distribution with (m-1)(n-1) degrees of freedom.

O​​​​​ij - observed frequency i​​​​​​throw and j​​​​​​th column

E​​​​​​ij - expected frequency i​​​​​​th row and j​​​​​​th column

"E_{ij} = \\frac{(i^{th} \\; row \\; total) \\times (j^{th} \\;column \\;total)}{N} \\\\\n\nE_{11} = \\frac{R_1 \\times C_1}{N} \\\\\n\n= \\frac{285 \\times 202}{500} = 115.14 \\\\\n\nE_{12} = \\frac{R_1 \\times C_2}{N} \\\\\n\n= \\frac{285 \\times 150}{500} = 85.5 \\\\\n\nE_{13} = \\frac{R_1 \\times C_3}{N} \\\\\n\n= \\frac{285 \\times 148}{500} = 84.36 \\\\\n\nE_{21} = \\frac{R_2 \\times C_1}{N} \\\\\n\n= \\frac{215 \\times 202}{500} = 86.86 \\\\\n\nE_{22} = \\frac{R_2 \\times C_2}{N} \\\\\n\n= \\frac{215 \\times 150}{500} = 64.5 \\\\\n\nE_{23} = \\frac{R_2 \\times C_3}{N} \\\\\n\n= \\frac{215 \\times 148}{500} = 63.64 \\\\\n\n\u03c7^2 = \\frac{138^2}{115.14} + \\frac{83^2}{85.5} + \\frac{64^2}{84.36} + \\frac{64^2}{86.86} + \\frac{67^2}{64.5} + \\frac{84^2}{63.64} - 500 \\\\\n\n= 22.0147"

Critical value or table value at

"(m-1)(n-1)=(2-1)(3-1)= 1 \\times 2=2" degrees of freedom and 5 % level of significance.

"Tab \\; \u03c7^2 = 5.991"

"Cal \\; \u03c7^2 > Tab \\; \u03c7^2"

Reject null hypothesis at 5 % level of significance.

There is enough evidence to conclude that the Party Affiliation and Opinion on Tax Reform are dependent at 5 % level of significance.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
APPROVED BY CLIENTS