Answer to Question #152025 in Statistics and Probability for JG

Question #152025
A survey was conducted among some first graders and one of the questions was how much money they spent on their school cafeteria. The random variable x represents the amount of money spent on a particular day with the corresponding probability P(X).

x 1 3 5 10 20
P(X) 0.16 ? 0.22 0.22 0.08


a) What is the probability that a 1st grader spends exactly 3 dollars?
b) Calculate the expected value, variance, and standard deviation of the random variable X?
1
Expert's answer
2020-12-21T19:36:43-0500

Solution:

a).


P(X=3)=1(0.16+0.22+0.22+0.08)P(X=3)= 1-(0.16+0.22+0.22+0.08)=0.32=0.32

b).

E(X)=xP(X=x)E(X) = \sum xP(X=x)

=1(0.16)+3(0.32)+5(0.22)+10(0.22)+20(0.08)

=6.02=6.02


Var(x)=x2P(x)(E(x))2Var(x) = \sum x^2 P(x) - {(E(x))} ^2

=12(0.16)+32(0.32)+52(0.22)=1^2(0.16)+3^2(0.32)+5^2(0.22)

+10(0.22)+20(0.08)+10(0.22)+20(0.08)


=62.54(6.02)2=62.54- {(6.02)}^2

= 26.2996


Standard deviation


Sd=varSd = \sqrt {var}

=26.2996=5.1283= \sqrt {26.2996} =5.1283


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