The provided sample variances are "s_1^2=52.3" and "s_2^2=89.9" and the sample sizes are given by "n_1=30" and "n_2=30."
The following null and alternative hypotheses need to be tested:
"H_0:\\sigma_1^2\\geq \\sigma_2^2"
"H_1:\\sigma_1^2< \\sigma_2^2"
This corresponds to a left-tailed test, for which a F-test for two population variances needs to be used.
Based on the information provided, the significance level is "\\alpha=0.1," and the the rejection region for this left-tailed test is "R=\\{F:F_L<0.617\\}."
The F-statistic is computed as follows:
Since from the sample information we get that "F=0.582<0.617=F_L," it is then concluded that the null hypothesis is rejected. Therefore, there is enough evidence to claim that the first instructor's variance of 52.3 is less than the second instructor's variance of 89.9, at the 10% level of significance.
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