Given :
n=10
p=0.2
conditions for binomial distribution:
The number of observations n is fixed. 2: Each observation is independent. 3: Each observation represents one of two outcomes ("success" or "failure"). 4: The probability of "success" p is the same for each outcome
since above conditions are satisfied , we use binomial distribution.
To find :
"P(x\\geq 3)"
Using binomial table for n= 10, p=0.2,x=3,
"P(x\\geq 3)"
= 1- P( x<3)= 1- 0.6778= 0.3222
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