i)Giventhat,μ=165,σ=25,n=60,then,P(x>158)=P(Z>25158−165)=P(Z>−0.28)=0.5+P(0<Z<0.28)=0.5+0.1103=0.6103numberofstudents=60×0.6103=36.63≈37ii)P(155<x<172)=P(25155−165)<Z<25172−165)=P(−0.4<Z<0.28)=P(0<Z<0.4)+P(0<Z<0.28)=0.1554+0.1103=0.2657numberofstudents=60×0.2657=15.94≈16
Comments
Thank you for this wonderful page it helps me a lot.
Dear helen, please use the panel for submitting a new question.
In a school with 500 students, the average height is 165 +-10 cm. Assuming that the height follows the normal distribution: If we choose a sample of 25 people from the above school: What is the probability that a student is taller than 169 cm? What is the probability that a student is less than 163 cm tall?