Question #122518
In Islamabad city the mean number of power outages is 4 per month. Find the
probability that in a given month,
a. There are exactly 3 outages
b. There are more than 2 outages.
1
Expert's answer
2020-06-17T18:55:50-0400

If your question has an average probability of an event happening per unit (i.e. per unit of time, cycle, event) and you want to find probability of a certain number of events happening in a period of time (or number of events), then use the Poisson Distribution


so x is the random variable that follows Poisson distribution


Given : μ=4\mu =4


formula: P(X=x)=eμμx/x!P(X=x) = e^{-\mu } \mu ^{x}/x!


a) To find : P(X=3)


P(X=3)= e4(43)/3!e^{-4 }(4 ^{3})/3! =0.1954


To find P(X>2)=1P(x2)P(X>2)=1-P(x\leq 2)

=1-[P(x=0)+P(x=1)+P(X=2)]

=1-(0.01832+0.07326+0.14653)

=0.76190



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