Let X be the random number of claims filed by policyholders. We know that the variance of a Poisson distribution is λ. But we have 4P(X = 4) = P(X = 2) that is 4e-λ (λ4/4!)=e-λ(λ2 /2!) ⇒4λ2/4!=1/2 ⇒ λ2 = 3⇐⇒ λ =1.732 hence the variance of X is equal to 1.732.
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Dear EVELYN, you have not mentioned which place or formula in the solution needs to be explained in detail.
please i need further explanation. i didnt understand your answer well
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