let T be a linear map on R3 Such that T(1,0,0)=(1,1,1),T(0,1,0)=(0,3,5),T(0,0,1)=(2,2,2)
a)find matrix A representing T with respect to the usual basis of R3
b)find matrix B representing T with respect to the basis S={(1,2,3),(2,3,4),(-1,0,1)}
Given that T(1,0,0) = (1,1,1), T(0,1,0) =(0,3,5) and T(0,0,1) =(2,2,2).
a) So matrix A with respect to the usual basis is
"A = \\begin{bmatrix} 1&0&2\\\\1&3&2\\\\ 1&5&2 \\end{bmatrix}"
b) In order to get the matrix with respect to the basis S, we need to get the linear transformation that led us to matrix A.
"T \\begin{bmatrix} a \\\\b \\\\c \\end{bmatrix} = \\begin{bmatrix} 1&0&2\\\\1&3&2\\\\ 1&5&2 \\end{bmatrix} \\begin{bmatrix} a \\\\b \\\\c \\end{bmatrix}"
i.e "T(a,b,c) = (a+2c,a+3b+2c,a+5b+2c)"
"T(1,2,3) = (1+2(3), 1+3(2)+2(3), 1+5(2)+2(3)) = (1+6,1+6+6,1+10+6) = (7,13,17)"
"T(2,3,4) = (2+2(4),2+3(3)+2(4),2+5(3)+2(4)) = (2+8, 2+9+8,2+15+8) = (10,19,25)"
"T(-1,0,1) =(-1+2(1),-1+3(0)+2(1),-1+5(0)+2(1)) = (-1+2,-1+2,-1+2) =(1,1,1)"
So, the matrix B representing T with respect to the basis S is
"B= \\begin{bmatrix} 7&10&1 \\\\13&19&1\\\\17&25&1 \\end{bmatrix}"
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