Question #159355

Let A and B be n × n matrices with A invertible. Prove that AB and BA have the

same eigenvalues. 


1
Expert's answer
2021-02-04T06:31:00-0500

Let A and B be n × n matrices with A invertible.

using the statement: if two matrices have the same characteristic equation, then they will have the same eigenvalues.

therefore in this solution, we will show that AB and BA have the same characteristic equation.

consider,

CAB = characteristic polynomial of a matrix AB

= |AB-λI\lambda\Iota | since, |A| denotes the determinatnt of matrix A

= |ABAA-1 - λ\lambda AA-1|

= | A(BA - λ\lambdaI\Iota )A-1| \because A is invertible, therefore AA-1 = I\Iota

= |A|.|BA - λ\lambdaI\Iota|.|A-1|

= |A|.|BA - λ\lambdaI\Iota|.1A\frac{1}{|A|}

= |BA - λ\lambdaI\Iota| = characteristic polynomial of matrix BA = CBA


Hence,

both AB and BA have the same characteristic polynomial (equation)

by using the above statement AB and BA will have the same eigenvalues.



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