Question #155057

Let {(1, 1, 1, 1), (1, 2, 1, 2)} be linearly independent which is a subset of vector space V4. Extend it to a basis of V4

Expert's answer

In vector space V4V_4 any four linearly independent vectors form a basis. Let us extend

{(1,1,1,1),(1,2,1,2)}\{(1, 1, 1, 1), (1, 2, 1, 2)\} to {(1,1,1,1),(1,2,1,2),(0,0,1,0),(0,0,0,1)}\{(1, 1, 1, 1), (1, 2, 1, 2), (0,0,1,0),(0,0,0,1)\}.



Since ∣1111121200100001∣=∣1111010100100001∣=1≠0,\left|\begin{array}{cccc} 1 & 1 & 1 & 1\\ 1 & 2 & 1 & 2\\ 0 & 0 & 1 & 0\\ 0 & 0 & 0 & 1 \end{array} \right|= \left|\begin{array}{cccc} 1 & 1 & 1 & 1\\ 0 & 1 & 0 & 1\\ 0 & 0 & 1 & 0\\ 0 & 0 & 0 & 1 \end{array} \right|=1\ne 0, we conclude that the vectors


(1,1,1,1),(1,2,1,2),(0,0,1,0),(0,0,0,1)(1, 1, 1, 1), (1, 2, 1, 2), (0,0,1,0),(0,0,0,1) are linearly independent, and thus form a basis of V4.V_4.



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