Let T:R2→R2 such that T(x1,x2)=(2x2−2x1,x1−x2).
We can see that;
T(0,0)=(2.0−2.0,0−0)⟹T(0,0)=(0,0)pre-multiply T−1 to both sides⟹(0,0)=T−1(0,0)⟹T−1(0)=0
Also, we can see that;
Ker(T):={(x1,x2)∣x1=x2}
And, the basis of Ker(T)={(1,1)}⟹dim(Ker(T))=1
Hence, T is not one-to-one
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