Given quadratic form is "x_1^2+2x_2x_3"
compare the given quadratic expression with standard quadratic form,
"ax_1^2+by_1^2+cz_1^2+2fyz+2gzx+2hxy"
we get,
a=1,b=0,c=0,f=1,g=0 and h=0
Transforming the quadratic equation into matrix form
So the required matrix is ,
"A=\\begin{bmatrix}\n a & h &g\\\\\n h& b&f\\\\\n g&f&c\n \n\\end{bmatrix}" , "A=\\begin{bmatrix}\n 1 & 0 &0\\\\\n 0& 0&1\\\\\n 0&1&0\n \n\\end{bmatrix}"
Using characterstics Equation "(A-\\lambda I)X=0"
To calculate the values of "\\lambda"
"|A-\\lambda I|=0"
"\\begin{vmatrix}\n 1 & 0 &0\\\\\n 0& 0&1\\\\\n 0&1&0\n \n\\end{vmatrix}-\\lambda \\begin{vmatrix}\n 1& 0 &0\\\\\n 0& 1&0\\\\\n 0&0&1\n\\end{vmatrix}=0"
"\\begin{vmatrix}\n 1-\\lambda & 0 &0\\\\\n 0& -\\lambda&1\\\\\n 0&1&-\\lambda\n \n\\end{vmatrix}" =0
Using Factorization method
"(1-\\lambda)(\\lambda^2-1)=0"
so "\\lambda=1,-1,1" (these are the required eigen values)
S0 the required canonical form is
"\\lambda_1x^2+\\lambda_2y^2+\\lambda_3z^2=0"
"x^2-y^2+z^2=0"
This is the required canonical form.
Comments
Dear MANCHU SAI VENKATA KIRAN, please use the panel for submitting a new question.
6x2+3y2+3z2-4xy-2yz+4xz reduce the quadratic from to canonical and find it's nature
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